三数之和

给你一个包含n个整数的数组nums,判断nums中是否存在三个元素a,b,c,使得a + b + c = 0?请你找出所有和为0且不重复的三元组。

注意:答案中不可以包含重复的三元组。

  • 示例 1:

    输入:nums = [-1,0,1,2,-1,-4]
    输出:[[-1,-1,2],[-1,0,1]]
  • 示例 2:

    输入:nums = []
    输出:[]
  • 示例 3:

    输入:nums = [0]
    输出:[]

提示:

  • 0 <= nums.length <= 3000
  • -105 <= nums[i] <= 105

Solution

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#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

class Solution {
public:
vector<vector<int>> threeSum(vector<int>& nums) {
vector<vector<int>> results;
if (nums.size() < 3) {
return results;
}
sort(nums.begin(), nums.end());
int len = nums.size();
for (int i = 0; i < len - 2; ++i) {
if (i > 0 && nums[i] == nums[i - 1]) {
continue;
}
if (nums[i] + nums[i + 1] + nums[i + 2] > 0) {
break;
}
if (nums[i] + nums[len - 2] + nums[len - 1] < 0) {
continue;
}
int left = i + 1;
int right = len - 1;
while (left < right) {
int sum = nums[i] + nums[left] + nums[right];
if (sum < 0) {
left++;
} else if ( sum > 0) {
right--;
} else {
vector<int> result = {nums[i], nums[left], nums[right]};
results.emplace_back(result);
while (left < right && nums[left] == nums[left + 1]) {
left++;
}
left++;
while (left < right && nums[right - 1] == nums[right]) {
right--;
}
right--;
}
}
}
return results;
}
};


int main() {
vector<int> input;
vector<vector<int>> results;

input = {-1,0,1,2,-1,-4};
results = Solution().threeSum(input); // [[-1,-1,2],[-1,0,1]]
for (int i = 0; i < results.size(); ++i) {
for (int j = 0; j < results[i].size(); ++j) {
std::cout << results[i][j] << " ";
}
std::cout << std::endl;
}
}